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libssh2: remove $(FPIC) from TARGET_CFLAGS

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libssh2 already makes sure that the compiler emits position-independent
code. Adding $(FPIC) makes no difference. In addition the libssh2 build
system puts its own flag behind the CFLAGS, overriding whatever was set
before.

Signed-off-by: Sebastian Kemper <sebastian_ml@gmx.net>
This commit is contained in:
Sebastian Kemper
2018-02-24 11:45:16 +01:00
parent 8bd3bd86ad
commit 4ac9a2ae84
1 changed files with 1 additions and 3 deletions
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4
libs/libssh2/Makefile
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@@ -9,7 +9,7 @@ include $(TOPDIR)/rules.mk
PKG_NAME:=libssh2
PKG_VERSION:=1.8.0
PKG_RELEASE:=1
PKG_RELEASE:=2
PKG_SOURCE:=$(PKG_NAME)-$(PKG_VERSION).tar.gz
PKG_SOURCE_URL:=https://www.libssh2.org/download
@@ -41,8 +41,6 @@ define Package/libssh2/config
source "$(SOURCE)/Config.in"
endef
TARGET_CFLAGS += $(FPIC)
CONFIGURE_ARGS += \
--disable-examples-build \
--disable-silent-rules \